The counting rate observed from a radioactive source at t=0 was 1600 counts per second and at t=8s it was 100 counts per second. The counting rate observed as counts per second at t=4sec will be
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
400 cps
b
200 cps
c
300 cps
d
150 cps
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Activity, A=A02n here n =tTh ⇒100=16002n ⇒n=4 ⇒tTh=4 ⇒Th = t4=84= 2 sec Since t = 8 sec, it means that in 8 sec there are 4 half lives. So, after t = 4 sec, there are 2 half lives ∴n=tTh=42=2 Now, activity =A=A02n=160022=400 cps
The counting rate observed from a radioactive source at t=0 was 1600 counts per second and at t=8s it was 100 counts per second. The counting rate observed as counts per second at t=4sec will be