A cracker is thrown into air with a velocity of $$10$$ $$ms-1$$ at an angle of $$45$$° with the vertical. When it is at a height of (1/2) m from the ground, it explodes into a number of pieces which follow different parabolic paths. What is the velocity of centre of mass, when it is at a height of $$1$$ m from the ground? (Take$$, g $$=$$ $$10$$ $$ms-2)

Question

A cracker is thrown into air with a velocity of $$10$$ $$ms-1$$ at an angle of $$45$$° with the vertical. When it is at a height of (1/2) m from the ground, it explodes into a number of pieces which follow different parabolic paths. What is the velocity of centre of mass, when it is at a height of $$1$$ m from the ground? (Take$$, g $$=$$ $$10$$ $$ms-2)

Infinity Learn · Accepted Answer

During explosion of a cracker, path of centre of mass does not change. At height $$1$$ m,         v $$=$$ $$u2-2gh$$       (from$$ conservation of mechanical $$energy)            $$=$$ $$45$$ $$ms-1$$

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