A cracker is thrown into air with a velocity of 10 ms-1 at an angle of 45° with the vertical. When it is at a height of (1/2) m from the ground, it explodes into a number of pieces which follow different parabolic paths. What is the velocity of centre of mass, when it is at a height of 1 m from the ground? (Take, g = 10 ms-2)
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a
45 ms-1
b
25 ms-1
c
54 ms-1
d
5 ms-1
answer is A.
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Detailed Solution
During explosion of a cracker, path of centre of mass does not change. At height 1 m, v = u2-2gh (from conservation of mechanical energy) = 45 ms-1