First slide

Kinetic energy

Question

A cricket ball is hit for a six by the bat at an angle of 45⁰ to the horizontal with kinetic energy K. At the highest point, the kinetic energy of the ball is

Moderate

A

zero
B

K
C

K/2
D

$K / \sqrt{2}$

Solution

At highest point, speed will remain $\frac{1}{\sqrt{2}}$ times (= u cos 45⁰ ).
Therefore, kinetic energy will become 1/2 times.

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