First slide

Projection Under uniform Acceleration

Question

A cricket ball is hit for a six leaving the bat at an angle of 45° to the horizontal with kinetic energy K. At the top the kinetic energy of the ball is:

Easy

A

zero
B

K
C

K/2
D

$\frac{K}{\sqrt{2}}$

Solution

$K . E = \frac{1}{2} m {(ucosθ)}^{2} = {Kcos}^{2} 45^{o} = \frac{K}{2}$

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