A cricket ball of mass $$150$$ g has an initial velocity $$u=(3i^+4j^)ms-1$$ and a final velocity $$v=-(3i^+4j^)ms-1$$, after being hit. The change in momentum (final$$ momentum $$-$$ initial $$momentum) is (in$$ $$kg-ms-1)

Question

A cricket ball of mass $$150$$ g has an initial velocity $$u=(3i^+4j^)ms-1$$ and a final velocity $$v=-(3i^+4j^)ms-1$$, after being hit. The change in momentum (final$$ momentum $$-$$ initial $$momentum) is (in$$ $$kg-ms-1)

Infinity Learn · Accepted Answer

Given, $$u=(3i^+4j^)ms-1$$ and $$v=-(3i^+4j^)ms-1Mass$$ of the ball $$=$$ $$150$$ g $$=$$ $$0.15$$ kg ∴ ∆$$p=$$ Change in momentum            $$=$$ Final momentum $$-$$ Initial momentum $$=$$ mv $$-$$ mu           $$=m(v-u)=(0.15)$$[$$-(3i^+4j^)-(3i^+4j^)$$]           $$=(0.15)$$[$$-6i^-8j^)$$]$$=-$$[$$0.15$$×$$6i^+0.15$$×$$8j^)$$]           $$=-(0.9i^+1.20j^)$$ Hence, ∆$$p=-(0.9i^+1.2j^)$$

A cricket ball of mass 150 g has an initial velocity $u = (3 \hat{i} + 4 \hat{j}) {ms}^{- 1}$ and a final velocity $v = - (3 \hat{i} + 4 \hat{j}) {ms}^{- 1}$ , after being hit. The change in momentum (final momentum - initial momentum) is (in kg-ms^-1)

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A cricket ball of mass 150 g has an initial velocity u=(3i^+4j^)ms-1 and a final velocity v=-(3i^+4j^)ms-1, after being hit. The change in momentum (final momentum - initial momentum) is (in kg-ms-1)

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A cricket ball of mass 150 g has an initial velocity $u = (3 \hat{i} + 4 \hat{j}) {ms}^{- 1}$ and a final velocity $v = - (3 \hat{i} + 4 \hat{j}) {ms}^{- 1}$ , after being hit. The change in momentum (final momentum - initial momentum) is (in kg-ms^-1)