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Q.

A cricket fielder can throw the cricket ball with a speed ν0. If he throws the ball while running with speed μ at an angle θ to the horizontal, what is the effective angle to the horizontal at which the ball is projected in air as seen by a spectator?

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a

tan-1v0cosθu+v0sinθ

b

tan-1v0sinθu+v0cosθ

c

tan-1uv0cosθ+v0sinθ

d

tan-1v0sinθ+v0cosθu

answer is B.

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Detailed Solution

Consider the adjacent diagramInitial velocity in x-direction, ux=u+v0cosθInitial velocity in y-direction,  uy=v0sinθwhere, angle of projection is θNow, we can writetanθ=uyux=v0sinθu+v0cosθ⇒  θ=tan-1v0sinθu+v0cosθ
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