A cricketer can throw a ball to a maximum horizontal distance of $$100$$ m. With the same speed how much high above the ground can the cricketer throw the same ball?

Question

Infinity Learn · Accepted Answer

Let u be the velocity of projection of the ball. The ball will cover maximum horizontal distance when angle of projection with horizontal, θ $$=$$ $$450$$. ThenRmax $$=$$ $$u2gHere$$, Rmax $$=$$ $$100$$ m∴  $$u2g$$ $$=$$ $$100$$ m  ......iAs $$v2-u2$$ $$=$$  $$2asHere$$ v $$=$$ $$0$$ (At$$ highest point velocity is $$zero)a$$ $$=$$ $$-g$$, s $$=$$ H ∴  H $$=$$ $$u22g$$ $$=$$ $$1002$$ $$=$$ $$50$$ m  $$(Using$$ $$(i))

A cricketer can throw a ball to a maximum horizontal distance of 100 m. With the same speed how much high above the ground can the cricketer throw the same ball?

Remember concepts with our Masterclasses.

Ready to Test Your Skills?

free study material