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Questions  

A cricketer of height 2.5 m throws a ball at an angle 30º with the horizontal such that it is received by another cricketer of same height standing at a distance of 50 m from the first one.The maximum height attained by the ball from the ground is

a
3.6 m
b
6.1 m
c
7.2 m
d
9.7 m

detailed solution

Correct option is D

R = 50 mHR=14tan⁡θH=50413=7.2mfrom the ground height is 7.2 + 2.5 = 9.7 m

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