A cricketer hits a ball with a velocity $$25$$ $$m/s$$ at $$60o$$ above the horizontal. How far above the ground it passes over a fielder $$50m$$ from the bat (assume$$ the ball is struck very close to the $$ground)

Question

Infinity Learn · Accepted Answer

The horizontal component of velocity is given $$byVX=25cos$$⁡$$60$$∘$$=12$$⋅$$5m/sSimilarly$$, the vertical component of velocity is given $$byvy=25sin$$⁡$$60$$∘$$=12$$⋅$$5$$×$$3m/sTime$$ to cover $$50$$ metre distance $$t=5012$$⋅$$5=4secThe$$ vertical height x is given by (see$$ fig. $$10) $$x=Vxt$$−$$12g$$¯$$t2=12$$⋅$$53$$¯×$$4$$−$$12$$×$$9$$⋅$$8$$×$$16=8$$⋅$$2m$$

A cricketer hits a ball with a velocity 25 m/s at 60^o above the horizontal. How far above the ground it passes over a fielder 50m from the bat (assume the ball is struck very close to the ground)

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A cricketer hits a ball with a velocity 25 m/s at 60o above the horizontal. How far above the ground it passes over a fielder 50m from the bat (assume the ball is struck very close to the ground)

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A cricketer hits a ball with a velocity 25 m/s at 60^o above the horizontal. How far above the ground it passes over a fielder 50m from the bat (assume the ball is struck very close to the ground)