First slide

Stress and strain

Question

A cube of aluminium of sides 0.1 m is subjected to a shearing force of 100 N. The top face of the cube is displaced through 0.02 cm with respect to the bottom face. The shearing strain would be

Moderate

A

0.02
B

0.1
C

0.005
D

0.002

Solution

Shearing strain $ϕ = \frac{x}{L} = \frac{0.02 m}{10 cm} ∴ ϕ = 0.002$

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