A cube of mass m and side length ‘a’ wettable by water (contact angle ), floats on the surface of water. Distance between the lower face of cube and the surface of water is aN. Value of N is (Take m=ρa33; surface tension of water =ρa2g24 where ρ is density of water)

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answer is 2.

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Detailed Solution

∴a2xρg=mg+4aσ⇒x=mg+4aσa2ρg⇒x=ρa3g3+4a×ρa2g24a2ρg⇒x=a3+a6=a2

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