A cube of metal is subjected to a hydrostatic pressure of 4 GPa. The percentage change in the length of the side of the cube is close to :(Given bulk modulus of metal, B=8×1010 Pa)
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a
5
b
1.67
c
20
d
0.6
answer is B.
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Detailed Solution
Bulk Modulus=B=-ΔPΔVV⇒-ΔVV=ΔPB⇒-3Δℓℓ=ΔPB [Since, volume of cube=V=ℓ3]⇒Δℓℓ=13ΔPB=13×4×1098×1010=160⇒Δℓℓ×100=160×100=1.67%