First slide

Fluid statics

Question

A cube is shifted to a depth of 100 m is a lake. The change in volume is 0.1%. The bulk modulus of the material is nearly

Easy

A

10 Pa
B

$10^{4} P a$
C

$10^{7} P a$
D

$10^{9} P a$

Solution

10 m column of water exerts nearly l atmosphere pressure. So, 100 m column of water exerts nearly 10 atmosphere pressure,
i.e., 10 × $10^{5}$ Pa or $10^{6}$ Pa. Now,
$K = \frac{(Δ P) V}{Δ V} = \frac{10^{6} \times 100}{0.1} P a = 10^{9} P a$

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