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Q.

A cube of side 2 m is placed in front of a concave mirror of focal length I m with its face A at a distance of 3 m and face B at a distance of 5 m from the mirror, The distance between the images of face A and B and height of images of A and B are respectively.

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a

I m,0.5 m,0.25 m

b

0.5 m, 1 m,0.25 m

c

0.5 m,0.25 m, 1 m

d

0.25 m, 1 m,0.5 m.

answer is D.

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Detailed Solution

For A  u=-3 m             v1=?,                 f=-1 m 1u1=1f-1u=1-1=13=1=-23   or v1=-32 For B 1v2=1-1-1-5 or 1v2=15-1=-45 or   v2=54m now,   v1-v2=32--54 =-32+54=-14m=-0.25 m Again,   I1O=v1u or I2=v1uO=--32-13=-1 m Again   I2O=-v2u or   I2=-541-52=-0.5 m
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