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Q.

A cube with a mass m = 20 g wettable by water floats on the surface of water. Each side of the cube has length l = 3 cm. The angle of contact between water and glass is zero degree and the surface tension of the water is 7.5 × 10–2 N/m. The distance between the lower face of the cube and the surface of the water is

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answer is 00002.32.

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Detailed Solution

Fupthrust =Fsurface tension + Weight P2xρg=4lT+mg(.03)2×103×10=.009+.29x=.209x=.02322m=2.322cm
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