A cube with a mass m = 20 g wettable by water floats on the surface of water. Each side of the cube has length l = 3 cm. The angle of contact between water and glass is zero degree and the surface tension of the water is 7.5 × 10-2 N/m. The distance between the lower face of the cube and the surface of the water is
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a
20/22 cm
b
2.222 cm
c
2.322 cm
d
2.434 cm
answer is C.
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Detailed Solution
FUptthrust= FSurface tension + Weightl2xrg = 4lT + mg (.03)2× 103 × 10 = .009 + .2 9x = .209 x = .02322 m = 2.322 cm
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A cube with a mass m = 20 g wettable by water floats on the surface of water. Each side of the cube has length l = 3 cm. The angle of contact between water and glass is zero degree and the surface tension of the water is 7.5 × 10-2 N/m. The distance between the lower face of the cube and the surface of the water is