A cube with a mass m = 20 g wettable by water floats on the surface of water. Each side of the cube has length l = 3 cm. The angle of contact between water and glass is zero degree and the surface tension of the water is 7.5 × 10-2 N/m. The distance between the lower face of the cube and the surface of the water is

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20/22 cm

2.222 cm

2.322 cm

2.434 cm

answer is C.

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Detailed Solution

FUptthrust= FSurface tension + Weightl2xrg = 4lT + mg (.03)2× 103 × 10 = .009 + .2 9x = .209 x = .02322 m = 2.322 cm

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