Q.

A cubical block of glass of refractive index n1, is in contact with the surface of water of refractive index n2. A beam of light is incident on vertical face of the block (see figure). After refraction, a total internal reflection at the base and refraction at the opposite vertical face, the ray emerges out at an angle θ. The value of θ is given by

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a

sinθ

b

tanθ

c

sinθ<1n12−n22

d

tanθ<1n12−n22

answer is A.

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Detailed Solution

n1sin⁡θC=n2⇒sin⁡θC=n2n11×sin⁡θ=n1sin⁡90∘−θC=n1cos⁡θC=n11−n22n12θ=sin−1⁡n12−n22;sin⁡θ
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A cubical block of glass of refractive index n1, is in contact with the surface of water of refractive index n2. A beam of light is incident on vertical face of the block (see figure). After refraction, a total internal reflection at the base and refraction at the opposite vertical face, the ray emerges out at an angle θ. The value of θ is given by