Q.

A cubical block of iron, 5cm on each side is floating in mercury taken in a vessel. What is the height of the block above mercury level. (ρHg=13.6g/cm3,ρFe=7.2g/cm3)

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a

2.35cm

b

0.5cm

c

0.15cm

d

3.15cm

answer is A.

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Detailed Solution

From the law of floatation, Vbρb=VinρL ∴     (5cm)3×(7.2g/cm3)=(52×xcm3)×(13.6g/cm3);   ∴   x=2.65cm
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A cubical block of iron, 5cm on each side is floating in mercury taken in a vessel. What is the height of the block above mercury level. (ρHg=13.6g/cm3,ρFe=7.2g/cm3)