A cubical block of iron, 5cm on each side is floating in mercury taken in a vessel. What is the height of the block above mercury level. (ρHg=13.6g/cm3,ρFe=7.2g/cm3)
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a
2.35cm
b
0.5cm
c
0.15cm
d
3.15cm
answer is A.
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Detailed Solution
From the law of floatation, Vbρb=VinρL ∴ (5cm)3×(7.2g/cm3)=(52×xcm3)×(13.6g/cm3); ∴ x=2.65cm