A cubical block of mas ‘M’ and edge ‘a’ slides down a rough inclined plane of inclination 'θ' with a uniform velocity. The torque of the normal force on the block about its center has a magnitude
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answer is 4.
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Detailed Solution
Since the block does not to topple, torque produced by normal forces = Torque produced by frictional force fK=mg sin θ × a2.