A cubical block of mass M vibrates horizontally with amplitude of 4 cm and a frequency of 2 Hz. A small block of mass m is placed on the bigger block. In order that the smaller block does not slide on the bigger block, the minimum value of the coefficient of static friction between the two blocks is
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a
0.36
b
0.40
c
0.64
d
0.72
answer is C.
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Detailed Solution
μg>maximum acceleration in SHM, i.e. ω2A∴ μ>ω2Ag⇒ μ>(2πf)2×Ag⇒ μ>(2×3.14×2)2×4×10-210⇒ μ>0.631≈0.64