Questions
A cubical block of side a is moving with velocity v on a horizontal smooth plane as shown in fig. It hits a
ridge at point O. The angular speed of the block after it hits O is
a
3V/(4a)
b
3v/(2a)
c
3V(2a)
d
zero
detailed solution
Correct option is A
See fig By conservation of angular momentum, we haveIω=MV(a/2)Here , I=Ma26+Ma22=2Ma23∴ 2Ma23ω=Mva2ω=3v4aTalk to our academic expert!
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The moment of inertia (I) and the angular momentum (L) are related by the expression [J&K CET 2013]
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