A cubical block of wood 10 cm on a side floats at the interface between oil and water, as in Fig. with its lower face 2 cm below the interface. The density of the oil is 0.6 g cm-3. The gauge pressure at the lower face of the block is
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a
84 Pa
b
384 Pa
c
484 Pa
d
784 Pa
answer is D.
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Detailed Solution
P = Pressure due to l0 cm of oil column + Pressure due to 2 cm of water column= 10x0.6g+2x1g= 8g = 8 x 980 dyne cm-2= 8×98010Nm-2 = 784 Pa