First slide

Fluid statics

Question

A cubical block of wood of side 10 cm floats at the interface between an oil and water with its lower surface 2 cm below the interface. The heights of the oil and water columns are 10 cm each. Density of oil is 0.8g/c.c. The mass of the block is

Easy

A

720 gram
B

900 gram
C

960 gram
D

840 gram

Solution

ρ₀ = 0.8gm/cc
m = m_w + m₀
= ρ_wV_w + ρ₀V₀
ρ_wAh_w + ρ₀Ah₀
m = 1 x 10 x 10 x 2 + 0.8 x 10 x 10 x 8 = 200 + 640 = 840gram

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