A cubical block of wood of side a and density ρ floats in water of density 2ρ. The lower surface of the cube just touches the free end of a massless spring of force constant K fixed at the bottom of the vessel. The weight W put over the block so that it is completely immersed in water without wetting the weight is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
aa2ρg+K
b
a(aρg+2K)
c
aaρg2+2K
d
aa2ρg+K2
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Since density of block = 1/2(density of water), 50% of its volume is immersed in water.In the second case, half of the volume of the block is further immersed in water.Therefore, W = Extra upthrust + Spring force =a×a×a2×2ρ×g+Ka2=aa2ρg+K2