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A cubical body floats in a mercury bath with half of its volume submerged. What fraction of the body will be inside mercury if a layer of water is poured on the mercury covers the body completely? (Sp. gr. of mercury = 13.6)

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answer is 00000.46.

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Detailed Solution

W=V2ρHgg......................(1)W=xVρHgg+(1−x)∨ρwg .....(2) From (i) and (ii) V2ρHgg=xVρHgg+(1−x)∨ρwg Solving we get x=0.46

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