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Q.

A cubical box dimension L = 5/4 m starts moving with an acceleration a→=0.5ms−2i^ from the state of rest. At the same time, a stone is thrown from the origin with velocity V→=v1i^+v2j^−v3k^ with respect to earth. Acceleration due to gravity g→=10ms−2(−j^). The stone just touches the roof of box and finally falls at the diagonally opposite point. then:

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a

v1=32

b

v2=5

c

v3=54

d

v3=52

answer is A.

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Detailed Solution

H=uy22g⇒uy=V2=5ms−1T=2usin⁡θg=2uyg=1sL=uxt−12axt254=ux×1−12×(0.5)×(1)2⇒ux=V1=3/2ms−1 Along z axis 54=uz×1⇒vz=54ms−1
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