Questions
A Cubical frame is made by connecting 12 identical uniform conducting rods as shown in the figure. In the steady state the temperature of junction A is while that the G is . Then,
detailed solution
Correct option is B
AB:100−T1=RΔQΔt−−−−1 or100−T1=RiBC:T1−T2=RΔQ2Δt −−−−2CA:T2=RΔQΔt −−−−32÷3T1−T2T2=RΔQ2ΔtRΔQΔt⇒T1−T2T2=12⇒2T1−2T2=T2⇒2T1=3T2⇒T1=3T22−−−−4From 1 and 3⇒100−T1=T2−−−5from 4 and 5⇒100−3T22=T2⇒100=5T22⇒T2=40°Csubstitute in 4⇒T1=3402=60°CTemperature of B,E,D (60°C) is hotter than H,F,C(40°C)Similar Questions
Two rods of equal length and diameter have thermal conductivities 3 and 4 units respectively. If they are joined in series, the thermal conductivity of the combination would be:
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