A Cubical frame is made by connecting 12 identical uniform conducting rods as shown in the figure. In the steady state the temperature of junction A is  1000C while that the G is 00C. Then,

AB:100−T1=RΔQΔt−−−−1 or100−T1=Ri​BC:T1−T2=RΔQ2Δt −−−−2​CA:T2=RΔQΔt        −−−−3​2÷3​T1−T2T2=RΔQ2ΔtRΔQΔt​⇒T1−T2T2=12​⇒2T1−2T2=T2​⇒2T1=3T2​⇒T1=3T22−−−−4​​From 1 and 3​⇒100−T1=T2−−−5​from 4 and 5​⇒100−3T22=T2​⇒100=5T22​⇒T2=40°C​substitute in 4​⇒T1=3402=60°C​​Temperature of B,E,D (60°C) is hotter than H,F,C(40°C)