Questions

# A Cubical frame is made by connecting 12 identical uniform conducting rods as shown in the figure. In the steady state the temperature of junction A is  ${100}^{0}\text{C}$ while that the G is ${0}^{0}\text{C}$. Then,

## Unlock the full solution & master the concept.

Get a detailed solution and exclusive access to our masterclass to ensure you never miss a concept
By Expert Faculty of Sri Chaitanya
a
H will be Hotter than B
b
Temperature of F is 400C
c
Temperature of D is 66.670C
d
Temperature of E is 500C
NEW

Check Your Performance Today with our Free Mock Tests used by Toppers!

detailed solution

Correct option is B

AB:100−T1=RΔQΔt−−−−1 or100−T1=Ri​BC:T1−T2=RΔQ2Δt −−−−2​CA:T2=RΔQΔt        −−−−3​2÷3​T1−T2T2=RΔQ2ΔtRΔQΔt​⇒T1−T2T2=12​⇒2T1−2T2=T2​⇒2T1=3T2​⇒T1=3T22−−−−4​​From 1 and 3​⇒100−T1=T2−−−5​from 4 and 5​⇒100−3T22=T2​⇒100=5T22​⇒T2=40°C​substitute in 4​⇒T1=3402=60°C​​Temperature of B,E,D (60°C) is hotter than H,F,C(40°C)

Similar Questions

Two rods of equal length and diameter have thermal conductivities 3 and 4 units respectively. If they are joined in series, the thermal conductivity of the combination would be:

Get your all doubts cleared from
Sri Chaitanya experts

+91