First slide
Magnetic field due to a current carrying circular ring
Question

A cument is passed in an equilateral triangle of side l and made of a uniform conducting wire as shown in fig. The magnetic induction at centre O will be

Easy
Solution

The current distribution is shown in fig. The magnetic induction at 0 is given by
B=BAB+BBC+BAC
=μ0(i/3)4π(l/23)+μ0(i/3)4π(l/23)μ0(2i/3)4π(l/23)2sin60
=0
 

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