First slide

Cell

Question

A current of 2A flows through a 2 $Ω$ resistor when connected across a battery. The same battery supplies a current of 0.5A when connected across a 9 $Ω$ resistor. The internal resistance of the battery is :

Easy

A

0.5 $Ω$
B

1/3 $Ω$
C

1/4 $Ω$
D

1 $Ω$

Solution

Let internal resistance of battery be r then according to question
$\frac{E}{2 + r} = 2 and \frac{E}{9 + r} = 0.5 \Rightarrow r = \frac{1}{3} Ω$

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