Questions
A current of 2A is increasing at a rate of 4 A/s through a coil of inductance 2H. The energy stored in the inductor per unit time is
detailed solution
Correct option is C
Potential difference across coil is V=Ldidt or V = (2) (4) = 8 VNow energy stored per unit time= power = Vi= (8) (2)= 16 J/sTalk to our academic expert!
Similar Questions
Two different coils have self-inductances L1 = 8 mH, L2 =2 mH. The current in one coil is increased at aconstant rate. The current in the second coil is also increased at the same rate. At a certain instant of time, the power given to the two coils is the same. At that time the current, the induced voltage and the energy stored in the first coil are i1 V1and W1 respectively. Corresponding value for the second coil at the same instant are i2, V2 and W2 respectively. Then
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