First slide
Inductance
Question

A current of 2A is increasing at a rate of 4 A/s through a  coil of inductance 2H. The energy stored in the inductor per unit time is

Moderate
Solution

Potential difference across coil is V=Ldidt 

or   V = (2) (4)  =  8 V

Now energy stored per unit time

= power = Vi

= (8) (2)
= 16 J/s

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