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Q.

A current of 2A is increasing at a rate of 4 A/s through a  coil of inductance 2H. The energy stored in the inductor per unit time is

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a

2 J/s

b

1 J/s

c

16 J/s

d

4 J/s

answer is C.

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Detailed Solution

Potential difference across coil is V=Ldidt or   V = (2) (4)  =  8 VNow energy stored per unit time= power = Vi= (8) (2)= 16 J/s
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A current of 2A is increasing at a rate of 4 A/s through a  coil of inductance 2H. The energy stored in the inductor per unit time is