First slide

Ohm's law

Question

The current in the adjoining circuit will be

Easy

A

$\frac{1}{45} ampere$
B

$\frac{1}{15} ampere$
C

$\frac{1}{10} ampere$
D

$\frac{1}{5} ampere$

Solution

$\begin{array}{l} R_{equivalent} = \frac{(30 + 30) 30}{(30 + 30) 30} = \frac{60 \times 30}{90} = 20 Ω \\ ∴ i = \frac{V}{R} = \frac{2}{20} = \frac{1}{10} ampere \end{array}$

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