Q.

The current in the adjoining circuit will be

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a

145  ampere

b

115  ampere

c

110  ampere

d

15  ampere

answer is C.

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Detailed Solution

Requivalent  =  30+303030+3030 =  60 ×  3090 = 20  Ω∴   i=VR=220  =  110  ampere
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