First slide

Force on a current carrying wire placed in a magnetic field

Question

A current carriyng straight conductor OA lies along x-axis. In that region a magnetic field of induction B exists whose direction is inward and magnitude of ‘B’ increases as we are moving along positive x-axis. If C be the mid point of the rod OA, then select the correct option.

Moderate

A

The resultant force acts at point C.
B

The resultant force acts at a point which lies between C and A
C

The resultant force acts at a point which lies between C and O.
D

None of the above is correct

Solution

If we consider a small element $∆ l$ of the rod, then magnetic force acting on the element is $∆ F = i . ∆ l . B$ . Where B is the magnetic induction at the location of $∆ l$ . If B is uniform , the resultant force acts at C. Since B is increasing as we are moving along positive x-axis the line of action of resultant force shifts to the right. Hence option -(2) is correct.

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