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Q.

A current carrying loop ABCDA is carrying a current I. O is the centre of the semi circle ADC, ABC = 900 and AB = BC = l. Then magnetic induction at o is

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a

1π+12μoΙ2l

b

8π+122μoΙl

c

4π+12μoΙl

d

2π+122μoΙl

answer is D.

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Detailed Solution

Bo = 2×μoΙ4πl22sin450+μoΙ4l2=2μoΙπl+μoΙ22l=μoΙl 2π+122
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