A current carrying loop ABCDA is carrying a current I. O is the centre of the semi circle ADC, ABC = 900 and AB = BC = l. Then magnetic induction at o is
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a
1π+12μoΙ2l
b
8π+122μoΙl
c
4π+12μoΙl
d
2π+122μoΙl
answer is D.
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Detailed Solution
Bo = 2×μoΙ4πl22sin450+μoΙ4l2=2μoΙπl+μoΙ22l=μoΙl 2π+122