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Q.

A current carrying wire is bent in the form of a circular ring and its magnetic dipole moment is found to be M. Now the same wire is bent in the form of a circular ring having two turns. Then new magnetic moment will be

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a

M/2

b

M/4

c

2 M

d

4 M

answer is A.

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Detailed Solution

M=πr2i and r=l2π⇒M=πl2i4π2=l2i4πIn the second case, 2πr1×2=l⇒r1=l4π∴M1=2×π(r1)2.i=2×π(l4π)2.i=l2i8π∴ M1=M2

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