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The current in the circuit of fig.is

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detailed solution

Correct option is D

Here, two resistances are in series. Their equivalent resistance is R1=3+3=6Ω The third resistance is in parallel. Hence equivalent resistance is given by1R=1R1+1R2=16+13=1+26=36=12∴ R=2ΩNow, i=VR=2V2Ω=1A

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