First slide

Diodes

Question

Current in the circuit will be

Easy

A

$\frac{1}{20} A$
B

$\frac{3}{20} A$
C

$\frac{5}{20} A$
D

zero

Solution

$U p p e r d i o d e i s i n r e v e r s e b i a s, n o c u r r e n t i n t h i s b r a n c h . L o w e r d i o d e i s i n f o r w a r d b i a s .$
$O h m' s L a w : I = \frac{3}{15 + 45} = \frac{1}{20} A$

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