First slide

Inductance

Question

The current in a coil of inductance 5 H decreases at the rate of 2 A/s. The induced e.m.f. is

Easy

A

2 V
B

5 V
C

10 V
D

$- 10 V$

Solution

$e = - L \frac{di}{dt}$ ; since current decreases, so $\frac{d i}{d t}$ is negative. Hence, $e = - 5 (- 2) = + 10 V$

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