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Questions  

The current in a coil of inductance 5 H decreases at the rate of 2 A/s. The induced e.m.f. is

a
2 V
b
5 V
c
10 V
d
- 10 V

detailed solution

Correct option is C

e=-Ldidt; since current decreases, so didt is negative. Hence,  e=-5(-2)=+10 V

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