First slide

Inductance

Question

The current flowing in a coil of self inductance 0.4 mH is increased by 250 mA in 0.1 sec. The e.m.f. induced will be

Moderate

A

+ 1 V
B

– 1 V
C

+ 1 mV
D

– 1 mV

Solution

$e = - L \frac{di}{dt} = - 0 .4 \times 10^{- 3} \times \frac{250 \times 10^{- 3}}{0 .1} = - 1 mV$

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