Questions
The current flowing in a coil of self-inductance 0.4 mH is increased by 250 mA in 0.1 s. The e.m.f. induced will be
detailed solution
Correct option is D
e=−Ldidt=−0.4×10−3×250×10−30.1=−1mVTalk to our academic expert!
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A coil is wound as a transformer of rectangular cross-section. If all the linear dimensions of the transformer are increased by a factor 2 and the number of turns per unit length of the coil remain the same, the self inductance increased by a factor of
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