First slide

electric current

Question

A current of 4.8 A is flowing in a conductor. The number of electrons passing per sec through the conductor will be :

Easy

A

$3 x 10^{19}$
B

$76.8 x 10^{20}$
C

$7.68 x 10^{20}$
D

$3 x 10^{20}$

Solution

$n = \frac{q}{e} = \frac{It}{e} = \frac{(4.8) (1)}{1.6 x 10^{- 19}} = 3 x 10^{19}$

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