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Q.

A current of 4.8 A is flowing in a conductor. The number of electrons passing per sec through the conductor will be :

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a

3 x 1019

b

76.8 x 1020

c

7.68 x 1020

d

3 x 1020

answer is A.

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Detailed Solution

n=qe=Ite=4.811.6 x 10-19=3 x 1019
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