First slide

Inductance

Question

Current flowing through a copper ring changes with time according to the graph shown in figure. If self inductance of the coil is 8 mH, the emf induced in the ring is

Moderate

A

16 mV
B

8 mV
C

12 mV
D

4 mV

Solution

$\frac{di}{dt} = - \frac{4}{2} A / s = - 2 A / s$
$ε = - L \frac{di}{dt} = - 8 \times (- 2) volt = 16 mV$

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