First slide

Force on a current carrying wire placed in a magnetic field

Question

A current of 10 A is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is

Easy

A

30⁰
B

45⁰
C

60⁰
D

90⁰

Solution

$\begin{array}{l} F = Bil \sin θ = \frac{F}{Bil} = \frac{15}{2 \times 10 \times 1 .5} = \frac{1}{2} \\ \Rightarrow θ = 30^{0} \end{array}$

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