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A current of 10 A is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is

a
300
b
450
c
600
d
900

detailed solution

Correct option is A

F=Bil sin θ  =FBil  =  152 × 10  ×  1.5  =  12⇒  θ = 300

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Two infinitely current carrying insulated wires AB and CD are carrying same current  I. The wires cross each other at right angles as shown in figure. Three identical conductors P1Q1 , P2Q2 and P3Q3, carrying same current are placed a shown in figure and the forces acting on them are F1 , F2 and F3 respectively. Then select the correct option.


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