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Q.

A current of 10 A is flowing in a wire of length 1.5 m. A force of 15 N acts on it when it is placed in a uniform magnetic field of 2 T. The angle between the magnetic field and the direction of the current is

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a

300

b

450

c

600

d

900

answer is A.

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Detailed Solution

F=Bil sin θ  =FBil  =  152 × 10  ×  1.5  =  12⇒  θ = 300
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