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Q.

Current I enters at A in a square loop of uniform resistance and leaves at B. The ratio of magnetic field at E, the center of square, due to segment AB to that due to DC is

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a

1

b

2

c

3

d

4

answer is C.

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Detailed Solution

Let current in AB is i1 and in DC is i2.i1i2=31 It is because resistance of AB will be one-third of that of ADCB. Now, B1B2=i1i2=3
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