A current I0 is flowing through on L – R circuit of time constant t0 . The source of current is switched off at time t = 0. Let r be the value of −dIdt at t = 0. Assuming this rate to be constant, the current will reduce to zero in a time interval of

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Detailed Solution

I=I0 e−t/to ⇒ −dIdt = I0t0 e−t/to. ∴ r= −dIdtt=0 = I0t0 ∴ The desired time is I0r or t0

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