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Q.

A current I0  is flowing through on L – R circuit of time constant t0 . The source of current is switched off at time t = 0. Let r be the value of −dIdt at t = 0. Assuming this rate to be constant, the current will reduce to zero in a time interval of

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Detailed Solution

I=I0  e−t/to  ⇒  −dIdt  = I0t0  e−t/to.      ∴    r= −dIdtt=0  = I0t0 ∴              The desired time is I0r or t0
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A current I0  is flowing through on L – R circuit of time constant t0 . The source of current is switched off at time t = 0. Let r be the value of −dIdt at t = 0. Assuming this rate to be constant, the current will reduce to zero in a time interval of