The current I1 (in A) flowing through 1Ω resistor in the following circuit is
0.2
0.4
0.5
0.25
In upper branch 1Ω and 1Ω are in parallel, which is in series with 2Ω.The equivalent resistance of upper branch is 0.5Ω + 2Ω = 2.5ΩMain current in upper branch =I=12.5=0.4A This will be divided equally in 1Ω branches. I1=I2=0.42=0.2A