Q.
The current I1 (in A) flowing through 1Ω resistor in the following circuit is
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a
0.2
b
0.4
c
0.5
d
0.25
answer is A.
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Detailed Solution
In upper branch 1Ω and 1Ω are in parallel, which is in series with 2Ω.The equivalent resistance of upper branch is 0.5Ω + 2Ω = 2.5ΩMain current in upper branch =I=12.5=0.4A This will be divided equally in 1Ω branches. I1=I2=0.42=0.2A
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