Q.

The current I1 (in A) flowing through 1Ω  resistor in the following circuit is

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a

0.2

b

0.4

c

0.5

d

0.25

answer is A.

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Detailed Solution

In upper branch 1Ω and 1Ω are in parallel, which is in series with 2Ω.​The equivalent resistance of upper branch  is 0.5Ω + 2Ω = 2.5ΩMain current in upper branch =I=12.5=0.4A  ​This will be divided equally in 1Ω branches. I1=I2=0.42=0.2A
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