A current I flows through a cylindrical rod of uniform cross-sectional area A and resistivity ρ. The electric flux through the shaded cross-section of rod as shown in figure is:
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a
Iρ
b
ρI
c
ρIA
d
ρAI
answer is B.
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Detailed Solution
The current density J, electric field E at the cross-section are related by J=EρMultiplying both side by A, we getJA=EAρ or I =ϕρ where ϕ is electric flux.or ϕ = ρI