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Q.

A current path shaped as shown in figure produces a magnetic field at P, the centre of the arc. If the arc subtends an angle of 30° and the radius of the arc is 0.6 m. What is the magnitude of the field at P, if the current is 3.0 A?

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a

2.62×10−6T

b

2.62×10−7T

c

3.62×10−7T

d

2.62×10−8T

answer is B.

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Detailed Solution

Magnetic field at centre of the circular loop,B=μ0Ni2RMagnetic field due to an arc of a circle at the centre,B=θ2πμ0i2R=μ04πiRθHere, θ=30∘ and i=3A,R=0.6m B=μ04π30.6π6=10−7×3×π0.6×6=2.62×10−7 T

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