First slide

Magnetic Flux

Question

current of SA. A coil of radius· 1 cm having 100 turns and a total resistance of 20 $Ω$ is placed inside the solenoid co-axially. The coil is connected to galvanometer. If current in the solenoid is reversed in direction. Find the charge flown through the galvanometer.

Easy

A

2 x 10^-4 C
B

1 x 10^-4 C
C

4 x 10^-4 C
D

8 x 10^-4 C

Solution

$B = μ_{0} n_{i} = 4 π x 10^{- 7} x 10^{4} x 5 = 2 π x 10^{- 2} r ϕ = BNA = 2 π x 10^{- 2} x 100 x \frac{π}{10^{4}} = 2 π^{2} x 10^{- 4} Charge = \frac{ϕ_{i} - ϕ_{2}}{R} = \frac{4 π^{2} x 10^{- 4}}{20} = 2 x 10^{- 4} C$

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