Questions
The current in self-inductance L = 40 mH is to be increased uniformly from 1 amp to 11 amp in 4 milliseconds. The e.m.f. induced in inductor during process is
detailed solution
Correct option is A
e=-LdidtGiven that, L = 40 x 10-3 Hdi = 77A - 1A = 10Aand dt = 4x 10-3 s∴e=40×10−3×104×10−3=100VTalk to our academic expert!
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A loop, having area 20cm2, is made of thin copper wire. If is placed in a uniform magnetic field of induction 1.5 Tesla with its plane perpendicular to the field. If area of the loop increases to 30 cm2 in 0.5 second, average emf induced in the loop is
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