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Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is

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a
40  Ω
b
25  Ω
c
250  Ω
d
500  Ω

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detailed solution

Correct option is C

Current sensitivity θi= 510−3  =  5000  divA        ....ivoltage sensitivity θV=20   divV        ....iii/ii we get  θ/iθ/V=500010 =250⇒      Vi=R=250  Ω

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Similar Questions

A moving coil galvanometer has 150 equal divisions. Its current sensitivity is 10 divisions per milliampere and voltage sensitivity is 2 divisions per millivolt. In order that each division reads 1 volt, the resistance in ohms needed to be connected in series with the coil will be

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