Current sensitivity of a moving coil galvanometer is 5 div/mA and its voltage sensitivity (angular deflection per unit voltage applied) is 20 div/V. The resistance of the galvanometer is
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a
40 Ω
b
25 Ω
c
250 Ω
d
500 Ω
answer is C.
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Detailed Solution
Current sensitivity θi= 510−3 = 5000 divA ....ivoltage sensitivity θV=20 divV ....iii/ii we get θ/iθ/V=500010 =250⇒ Vi=R=250 Ω